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What is Newton’s First Law of Motion? [Simple Explanation]

What is Newton's First Law of Motion? [Simple Explanation]

What is Newton’s Second Law of Motion? [Easy Explanation]

What is Newton's Second Law of Motion? [Easy Explanation]

What is Newton’s Third Law of Motion?

What is Newton's Third Law of Motion?

3 Newton’s Laws of Motion [With Examples in Everyday Life]

3 Newton's Laws of Motion [With Examples in Everyday Life]

Newton’s Second Law of Motion: Real Life Examples + Pictures

Newton's Second Law of Motion: Real Life Examples + Pictures

Newton’s Second Law of Motion [Equation/Formula + Problems]

Newton's Second Law of Motion [Equation/Formula + Problems]

Simple Definition of Newton’s Second Law (A Quick Look)

Simple Definition of Newton's Second Law of Motion (A Quick Look)

Newton’s Third Law of Motion (Real Life Examples + Pictures)

Newton's Third Law of Motion (Real Life Examples + Pictures)

What is Newton’s Law of Cooling? (Differential Equation + Graph)

What is Newton's Law of Cooling? (Differential Equation + Graph)

What is Newton’s Law of Inertia? [Practical Explanation]

What is Newton's Law of Inertia? [Practical Explanation]

Newton’s Universal Law of Gravitation | Definition, Formula and Example

Newton's Law of Universal Gravitation | Definition, Formula and Example

How many Newton’s Laws are there? (What are they?)

How many Newton's Laws are there? (What are they?)

Newton’s First Law of Motion (Real Life Examples + Pictures)

Newton's First Law of Motion (Real Life Examples + Pictures)

Newton’s Law of Cooling Formula (Explained with Derivation)

Newton's Law of Cooling Formula (Explained with Derivation)

Newton’s Law of Inertia Examples (With Pictures)

Newton's Law of Inertia Examples (With Pictures)

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The answer is B.

GIven data:
mass = 4 kg
velocity = 10 m/s
momentum =?

According to formula of momentum,
p = mv
p = 4(10)
p = 40 kg m/s

The answer is A.

From the figure,
gravitational force acting on skydiver = 800 N
air resistance force acting on skydiver = 800 N
mass of skydiver = 100 kg

So,

net force,
F = 800 – 800
F = 0 N

acceleration,
a = F / m
a = 0 / 100
a = 0 m/s2

The answer is B.

From the figure,
gravitational force acting on skydiver = 800 N
air resistance force acting on skydiver = 600 N
mass of skydiver = 100 kg

So,

net force,
F = 800 – 600
F = 200 N

acceleration,
a = F / m
a = 200 / 100
a = 2 m/s2

The answer is C.

From the figure,
gravitational force acting on skydiver = 800 N
air resistance force acting on skydiver = 250 N
mass of skydiver = 100 kg

So,

net force,
F = 800 – 250
F = 550 N

acceleration,
a = F / m
a = 550 / 100
a = 5.5 m/s2

The answer is D.

From the figure,
gravitational force acting on skydiver = 800 N
air resistance force acting on skydiver = 0 N
mass of skydiver = 100 kg

So,

net force,
F = 800 N

acceleration,
a = F / m
a = 800 / 100
a = 8 m/s2

The correct answer is B.

(In this case, Stone hits the ground first)

The correct answer is C.

(Both feather and a stone strike the ground at the same time)

The answer is B.

Given data:
initial velocity = 60 m/s
final velocity = 30 m/s
opposing force = – 4 N
mass = 400 grams = 0.4 kg
time = ?

According to Newton’s second law formula,
F = m (v – u) / t
(- 4) = 0.4 (30 – 60) / t
(- 4 × t) = 0.4 (- 30)
(- 4 × t) = – 12
4 t = 12
t = 12 / 4
t = 3 seconds

The answer is D.

Given data:
mass = 400 kg
initial velocity = 0 m/s
after time = 20 seconds
final velocity = 25 m/s
net force =?

According to Newton’s second law formula,
F = m (v – u) / t
F = 400 (25 – 0) / 20
F = 10000 / 20
F = 500 N

The answer is A.

Given data:
mass = 5 kg
initial velocity = 4 m/s
net force = (15 + 25) = 40 N
final velocity = ?
time = 10 seconds

According to Newton’s second law formula,
F = m (v – u) / t
40 = 5 (v – 4) / 10
5 (v – 4) = (40 × 10)
5 (v – 4) = 400
(v – 4) = 400 / 5
(v – 4) = 80
v = 80 + 4
v = 84 m/s

The answer is B.

Given data:
mass = 5 kg
initial velocity = 35 m/s
opposing force = – 15 N
final velocity = ?
time = 4 seconds

According to Newton’s second law formula,
F = m (v – u) / t
(- 15) = 5 (v – 35) / 4
5 (v – 35) = (- 15) × (4)
5 (v – 35) = – 60
(v – 35) = (- 60) / 4
(v – 35) = – 12
v = – 12 + 35
v = 23 m/s

The answer is D.

Given data:
mass = 1 kg
initial velocity = 0 m/s
net force = 5 N
final velocity = ?
time = 6 seconds

According to Newton’s second law formula,
F = m (v – u) / t
5 = 1 (v – 0) / 6
v = 5 × 6
v = 30 m/s

The answer is C.

Given data:
mass = 100 kg
initial velocity = 20 m/s
final velocity = 50 m/s
time = 4 seconds
net force =?

According to Newton’s second law formula,
F = 100 (v – u) / t
F = 100 (50 – 20) / 4
F = 100 (30) / 4
F = 25 (30)
F = 750 N

The answer is D.

Given data:
mass = 20 kg
momentum = 400 kg m/s
velocity =?

According to formula of momentum,
p = mv
v = p / m
v = 400 / 20
v = 20 m/s

The answer is C.

Given data:
velocity = 2 m/s
momentum = 2000 kg m/s
mass =?

According to formula of momentum,
p = mv
m = p / v
m = 2000 / 2
m = 1000 kg

The answer is D.

Given data:
mass = 5 kg
momentum = 25 m/s
velocity =?

According to formula of momentum,
p = mv
v = p / m
v = 25 / 5
v = 5 m/s

The answer is B.

Given data:
mass = 200 grams = 0.2 kg
velocity = 4 m/s
momentum =?

According to formula of momentum,
p = mv
p = 0.2(4)
p = 0.8 kg m/s

The answer is D.

Given data:
mass = 75 kg
momentum = 4500 kg m/s
velocity =?

According to formula of momentum,
p = mv
v = p / m
v = 4500 / 75
v = 60 m/s

The correct answer is A.

(As it is clearly mentioned in the question that friction and air resistance is neglected)
Therefore,
According to the question, the car will continue to stay in motion with the same speed and in the same direction.
(As there is no such friction and air resistance to slow down the car)

Always remember,
An external force is not needed to produce the motion of any object.
External force only helps in accelerating the object forward.
(Object will not change its behaviour if no external force is given to it)

The correct answer is B.

According to the viewpoint of Loki, he believes that whatever forces acting on the book are in balanced condition.
So, there is no such motion of the book possible in the horizontal direction.

BUT,
Balanced forces in Newton's first law of motion Remember this flowchart discussed in Newton’s first law?
If Loki has understood Newton’s laws properly, then he knows that…
If the friction and air resistance are neglected, there is no such kind of air drag, right.
So, the object starts moving in the horizontal direction. (Even if the forces are balanced)

Therefore, Sara is correct.

Always Remember,
An external force is not needed to produce the motion of any object.
External force only helps in accelerating the object forward.
(Object will not change its behaviour if no external force is given to it)

The correct answer is C.

Well, option B is also correct.
But, as it is clearly mentioned in the question, what if no external force is given to the ball?
(In fact, it is also given that the ball is moving with the uniform motion)

If you remember the first law, it is clearly mentioned that…
An object will change its behaviour only if an unbalanced force acts on it. (Otherwise NOT)

In short, remember this point:
An external force is not needed to produce the motion of any object.
External force only helps in accelerating the object forward.
(Object will not change its behaviour if no external force is given to it)

The answer is A.

Given data:
mass = 1000 kg
net force = 4500 N
acceleration =?

According to Newton’s second law,
F = ma
a = F / m
a = 4500 / 1000
a = 4.5 m/s2

The answer is C.

Given data:
acceleration = 4 m/s2
mass = 1.5 kg
net force =?

According to Newton’s second law,
F = ma
F = 1.5(4)
F = 6 N

The answer is B.

Given data:
net force = 6 N
acceleration = 3 m/s2
mass =?

According to Newton’s second law,
F = ma
m = F / a
m = 6 / 3
m = 2 kg

The answer is A.

Given data:
mass = 5 kg
acceleration = 4 m/s2
net force =?

According to Newton’s second law,
F = ma
F = 5(4)
F = 20 N

The answer is D.

Given data:
mass = 5 kg
net force = 15 N
acceleration =?

According to Newton’s second law,
F = ma
a = F / m
a = 15 / 5
a = 3 m/s2

The answer is C.

Given data:
acceleration = 3 m/s2
mass = 2 kg
net force =?

According to Newton’s second law,
F = ma
F = 2(3)
F = 6 N

The correct answer is C.

When the brake is applied by the truck driver, the force will act in the backward direction.
(as the direction of acceleration will be similar to that of force)

The correct answer is B.

When the truck is moving forward, the force will also act in the forward direction.
(as the direction of acceleration will be similar to that of force)

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